Question

EX.4 Find the minimum value of K such that p(X≤ k) > 0.72, where

x 0 1 2 3 4 5 6

P(X) 0.1 0.17 0.32 0.12 0.2 0.07 0.02​

Answer 1

Answer:

k=4

Step-by-step explanation:

below 3 the probability is 0.71

but for all k greater than or equal to 4 probability is is greater than .72

so value of k is 4.

here F(x) is cumulative function.