Question

Ex. 4. If 2 ^x- 1 + 2^x+1 = 1280, then find the value of x.
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Answer 1

Answer:

2^x ÷ 2^1 + 2^x × 2^1=1280

2^x(1/2+2)=1280

2^x(5/2)=1280

2^x=1280×2/5

2^x=256×2

2^x=512

2^x=2×2×2×2×2×2×2×2×2

2^x=2^9

x=9.

Answer 2

Answer:

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