ex 5.2 class 10 Q6 AP
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Step-by-step explanation- the question is- check whether -150 is a term of ap:11,8,5,2....
Answer-
Here a1=11, a2=8, a3=5, a4=2
Common difference= a2-a1= 8-11= -3
Therefore common difference(d) = -3
Let -150 be the nth term of the given ap.
Therefore an=-150
Or a+(n-1)d=-150
Or 11+(n-1)×(-3)=-150
Or (n-1)×(-3)=-150-11
Or (n-1)×(-3)= -161
Or n-1=-161/-3
Therefore n=161/3+1
= 161+3/3
=169/3
Since number of terms (n) cannot be in fraction.
Therefore -150 is not a term of the ap:11,8,5,2.....
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