Ex. 7. Prove that
cos 11° + sin 11°
cos 11°-sin 11°
= tan 56°
Answers
Answer:
So we are given in the L.H.S. and tan 56 in the R.H.S.
So, let's start solving the question from the L.H.S.
Now, let's start by dividing the numerator and the denominator by cos 11.
Simplify.
Now as we know that "tan 45° = 1", we'll replace the 1 to tan 45°.
Now let's simplify.
Now let's put the value of a and b in the above equation;
tan (45° +11°) = tan (56°) = R.H.S.
Hence, Proved
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cos 11 + sin 11 ÷
cos11 -sin 11
this is the L.H.S.
DIVIDING BOTH SIDES WITH cos 11
in the numerator :cos 11+sin11/cos 11
which is equal to. 1+sin11/cos11 =1+tan 11
in the denominator : cos11-sin11/cos11
=1-cos11/sin11
=1-tan11
so,1+tan11/1-tan11
tan 11 gets cancelled
so and is 1
next in the R.H.S.: tan 45 is 1
therefore it's proved