Question

Ex- 8.3

1. Evaluate

$ii) \frac{ \tan26degree }{ \cot64degree}$


$iv) \cos \sec31degree - 59degree$

[NCERT]

Class 10

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Answer 1

Hey!!

Refer to the attachment


Hope it helps:-)))

Answer 2

Hey mate!

Here is yr answer.....


1. tan 36° / cot 54°

As we know,

tan(90-Φ) = cotΦ

So,

=> tan(90-54)° / cot 54°

=> cot 54° / cot 54°

=> 1/1

=> 1


2. cosec 31° - sec 59°

As we know,

cosec(90-Φ) = secΦ

=> cosec(90-31)° - sec 31°

=> sec 31° - sec 31°

=> 0



Hope it helps u..


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