Question

Ex. & ball drops from a height 10m.Assurne acceleration has 10 m3, calculate the velocity with which it strikes he ground

Answer 1

Just a typing mistake :

We need to assume the acceleration to be 10 m/s² because m³ is not a unit of the acceleration due to gravity .

The height of the ball which drops (h) is given 10 m .

The acceleration due to gravity (g) = 10 m/s² .

According to Law of Conservation of energy :

we know that the potential energy when the ball drops = kinetic energy when the ball hits the ground .

Kinetic energy = potential energy at height h

⇒ K = m g h

K = 1/2 m v² such that v is the velocity of the body when it hits the ground .

1/2 m v² = m g h

⇒ v² = 2 g h

We get the equation and substituting the values we get :

⇒ v² = 2 × 10 m/s² × 10 m

⇒ v² = 200 m²/s²

⇒ v = √( 200 m²/s²)

⇒ v = √( 100 × 2 )

⇒ v = 10√2

⇒ v = 10√2 m/s

The velocity will be 10√2 m/s .