Question

Ex-h. Factorine
(1) 2a7 - 128a​

Answer 1

Answer:

$2a( {a}^{2} - 4)( {a}^{4} + 16 + 4 {a}^{2} )$

Step-by-step explanation:

$2 {a}^{7} - 128a \\ = 2a( {a}^{6} - 64) \\ = 2a( {( {a}^{2})}^{3} - {4}^{3} ) \\ = 2a( {a}^{2} - 4)( {a}^{4} + 16 + 4 {a}^{2} )$