Question

Ex.
Two beams of light having intensities I and 41 interfer to produce a fringe pattern on a screen. The phase
difference between the beam is
at point A and 21 at point B. Then find out the difference between the
resultant intensities at A and B.​

Answer 1

Resultant Intensity of two wave -

I= I_{1}+I_{2}+2\sqrt{I_{1}I_{2}}\cos \theta

- wherein

I_{1}= Intencity of wave 1

I_{2}= Intencity of wave 2

\theta = Phase difference

 

 

I_{A} = I+4I+2\sqrt{I.4I}.\cos \frac{\pi }{2} =5I

I_{B} = I+4I+2\sqrt{I.4I}.\cos \pi =I

I_{A}-I_{B} = 4I