ex4 ..elimination method ......do fast..
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first equation ,
ax + by -( a-b) = 0
ax + by = a-b -----(1) ×b
second equation,
bx - ay -(a+b) = 0
bx - ay = a + b -----(2) ×a
multiply b on (1) and a on (2) , we get
abx + b^2y =ab - b^2
abx - a^2y = a^2 +ab
solving (1) and (2) by elimination method we get ,
y(a^2 + b^2) = - (a^2 + b^2 )
y = -1
from this u can easily find the value of x
ax + by -( a-b) = 0
ax + by = a-b -----(1) ×b
second equation,
bx - ay -(a+b) = 0
bx - ay = a + b -----(2) ×a
multiply b on (1) and a on (2) , we get
abx + b^2y =ab - b^2
abx - a^2y = a^2 +ab
solving (1) and (2) by elimination method we get ,
y(a^2 + b^2) = - (a^2 + b^2 )
y = -1
from this u can easily find the value of x
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y=-1,. or baaki ka apne aap aa gaayga.............
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