Math, asked by Akshi2009, 10 months ago

exact
8. Find the least number which when divided by 6, '5 and 18 leave remainder 5 in e
case.
Want A digit number which is divisible by 18. 24 and 32​

Answers

Answered by Suhas107
0

Answer:

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case. Let us check our answer

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