Question

Exactly 0.2mol of electrons are passed through three electrolytic cells in series. One contains
silver ion, the next zinc ion, and the last iron(III) ion. Assume that the only cathode reaction in
each cell is the reduction of the ion to metal. How many grams of each metal will be deposited?

Answer 1

Answer:

here it is...................

Answer 2

Answer:

Explanation:

Are you from VIT?

For silver, the conversion is Ag+ + e- -> Ag  

Therefore 1 mole of electrons are reqd to make 1 mole i.e 108 gm of silver. hence 0.2 moles of electron will make 0.2x108 = 21.6 gm of silver.  

For zinc, the connversion is Zn2+ + 2e- -> Zn  

Therefore 2 moles of elctrons are reqd to make 1 mole i.e 65 gm of zinc, hence 0.2 mole electrons shall make 0.2x65/2 = 6.5 gm of zinc.  

 

21.6 grams of Silver metal will be deposited and 6.5 grams of Zinc will be deposited.