Question

Exactly 3.705 kg of Substance Y are needed to neutralise 100 moles of HCl. What could be substance Y?​

Answer 1

Explanation:

the substance should be a base

Answer 2

The question is incomplete, here is the complete question:

Exactly 3.705 kg of substance Y are needed to neutralise 100 moles of HCl(aq).

What could be substance Y?

A. Ca

B. CaO

C. Ca(OH)₂

D. CaCO₃

The substance Y is $Ca(OH)₂_2$

Explanation:

We are given:

Moles of HCl = 100 moles

We know that:

Calcium is a divalent atom and it reacts with 2 moles of HCl to produce a salt.

The chemical equation for the reaction of calcium ions and HCl follows:

$Ca^{2+}+2HCl\rightarrow CaCl_2+2H^+$

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium ions

So, 100 moles of HCl will react with = $\frac{1}{2}\times 100=50mol$ of calcium ions

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Mass of compound = 3.705 kg = 3705 g    (Conversion factor:  1 kg = 1000 g)

Moles of compound containing calcium ions = 50 moles

Putting values in above equation, we get:

$50mol=\frac{3705g}{\text{Molar mass of compound}}\\\\\text{Molar mass of compound}=\frac{3705g}{50mol}=74.1g/mol$

The compound having molar mass equal to 74.1 g/mol is calcium hydroxide

Learn more about acid-base reaction and number of moles:

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