Math, asked by yuvraajj9090, 6 months ago

Exam.01.12.2016)
136. If x^4 + 2x^3 + ax^2 + bx + 9 is a
perfect square, where a and b are
positive real numbers, then the
values of a and b are
(1) a = 5, b = 6
(2) a = 6, b = 7
(3) a = 7, b= 6
(4) a = 7, b = 8
(SSC CGL Tier-II Online
Exam.01.12.2016)​

Answers

Answered by partistharoy
1

not understand write proper questions

Answered by Anonymous
2

Answer:

c

Step-by-step explanation:

let \:  \\   {x}^{4}  +  {2x}^{3}  +  {ax}^{2}  + bx + 9  \\  =   {( {px}^{2}  + qx + r)}^{2}  \\  {( {px}^{2}  + qx + r)}^{2}  =  {p}^{2}  {x}^{4}  {2pqx}^{3}  \\ since \:   \\   {x}^{2} (2pr +  {q}^{2} ) + 2qrx  +  {r}^{2}

  • by equating coefficient of
  • x
  • we get,
  •  {p}^{2}  = 1 \\ pq = 1 \\  {r}^{2}  = 9 \\ a = 2pr +  {q}^{2}  \\ b = 2qr
  • since it is given that both
  • a
  • and
  • b
  • are positive real numbers, you will see
  • p = 1 = q \\ r = 3
  • thus,
  • a = 7
  • and
  • b = 6

please mark my answer as brainliest

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