Question

EXAM PAD
Surn of (0,2) (0,-2) is PA + PB =6​

Answer 1

A(X1,Y1)=(0,2) & B(X2,Y2)=(0,-2) & P(x,y)

PA+PB=6

(x-x1)^2+(y-y1)^2+(x-x2)^2+(y-y2)^2=(6)^2

(×-0)2+(y-2)2+(×-0)2+(y-(-2))2=36

×2+(y-2)2+×2+(y+2)2=36

×2+y2+4-4y+×2+y2+4+4y=36

2×2+2y2-4×+4y+8-36=0

2×2+2y2-4×+4y-28=0

Locus of (×,y) is x2+y2-2×+2y-14=0