examine if 1 and 2 are the zeroes of the polynomial p(x)=x³–3x²–x+3
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Step-by-step explanation:
If x= 1 then
p(1) = 1³ - 3(1)² - 1 + 3
= 1 - 3 - 1 + 3
= 0
If x= 2 then
p(2) = 2³ - 3(2)² - 2 + 3
= 8 - 12 - 2 + 3
= -3
Thus only 1 is the zero of the polynomial.
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