Examine that the list of numbers 13,10,7,4,... form an AP.If it form an AP,write the next two terms.
Answers
Step-by-step explanation:
Given :-
13,10,7,4,...
To find :-
Examine that the list of numbers 13,10,7,4,... form an AP.If it form an AP,write the next two terms?
Solution :-
Given list of numbers = 13 , 10, 7, 4,...
First term = 13
Common difference =d
=> d = 10-13 = -3
=> d = 7-10 = -3
=> d = 4-7 = -3
Since the common difference is same throughout the series.
Therefore, 13,10,7,4,... are in the AP.
Next two terms are 5th and 6th terms
5th term = 4-3 = 1
6th term = 1-3 = -2
or
We know that
nth term of an AP = an = a+(n-1)d
5th term = a 5 = a+(5-1)d = a+4d
=> 13+4(-3)
=> 13-12
=> 1
and 6th term = a6
=> a+(6-1)d
=> a+5d
=> 13+5(-3)
=> 13-15
=> -2
Answer:-
Given list of numbers are in the AP
The next two terms of the given AP are 1 and -2
Used Concept :-
If the common difference is same throughout the series then the list of numbers are in the AP.
Used formulae:-
nth term of an AP = an = a+(n-1)d
Where, a = First term
d = Common difference
n = number of terms
Answer :
1 and -2 are the next two terms.
Step-by-step Explanation :
difference between 1st and 2nd term -
13 - 10 = 3
difference between 2nd and 3rd term-
10-7 = 3
Difference between 3rd and 4th term-
7-4 = 3
Common difference is same , since it is an AP
And we have given 4 terms.
So, we have to find the 5th and the 6th term :-------
5th term = 4th term - common difference
= 4 - 3 = 1
6th term = 5th term - common difference
= 1 - 3 = -2
Thus, the next two terms i.e. 5th and 6th term is 1 and -2 respectively.
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Hope this helped you.
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