examine the convergence or divergence of the series (√n^3+1-√n^3)
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Step-by-step explanation:
Suppose I am given a infinite series as
∑n=1∞(n3+1)1/3−n
how can I tell that if it converges or diverges (by which test) , I applied D'alembert ratio test as
limn→∞((n+1)3+1)1/3−n−1(n3+1)1/3−n
but test fails as limit comes out to be 1 , so how to actually find nature?
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