Question

Examine the fact that g(x) =x-1, p(x) = 2x^3+x^2-2x-1​

Answer 1

Answer:

hope this would help....

Answer 2

Answer:

Yes, g(x) is a factor of p(x)

Step-by-step explanation:

$x - 1 = 0$

$x = 1$

Substitute the value of 'x' in p(x)

$2 {x}^{3} + {x}^{2} - 2x - 1$

$(2 \times {1}^{3}) + ({1}^{2} ) - (2 \times 1) - 1$

$2 + 1 - 2 - 1$

$3 - 3$

$0$

So, g(x) is a factor of p(x)

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