Question

Examine the isotopes.

hydrogen-3 (3H)
carbon-14 (14C)
oxygen-16 (16O)

Which one or more of these isotopes would be more likely to undergo nuclear decay, and why?

Hint: Hydrogen's atomic number = 1; carbon's atomic number = 6; oxygen's atomic number = 8

A) Carbon-14 and hydrogen-3 would be more likely to decay, because their neutrons and protons are not equal.
B) Carbon-14 and oxygen-16 would be more likely to decay, because their atomic numbers are higher.
C) Oxygen-16 would be more likely to decay, because it has the largest atomic mass.
D) Oxygen-16 would be more likely to decay, because its neutrons and protons are equal.
GUYS PLEASE HELP ASAP

Answer 1

Answer:

Option A

Explanation:

Oxygen 16 is its natural isotope. It is stable. But 3H and 14C are not stable. They are not thre in their natural states.