Examine the isotopes.
hydrogen-3 (3H)
carbon-14 (14C)
oxygen-16 (16O)
Which one or more of these isotopes would be more likely to undergo nuclear decay, and why?
Hint: Hydrogen's atomic number = 1; carbon's atomic number = 6; oxygen's atomic number = 8
A.Carbon-14 and hydrogen-3 would be more likely to decay, because their neutrons and protons are not equal.
B. Oxygen-16 would be more likely to decay, because it has the largest atomic mass.
C. Oxygen-16 would be more likely to decay, because its neutrons and protons are equal.
D.Carbon-14 and oxygen-16 would be more likely to decay, because their atomic numbers are higher.
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