Science, asked by nicolenix03, 11 months ago

Examine the isotopes.

hydrogen-3 (3H)
carbon-14 (14C)
oxygen-16 (16O)

Which one or more of these isotopes would be more likely to undergo nuclear decay, and why?

Hint: Hydrogen's atomic number = 1; carbon's atomic number = 6; oxygen's atomic number = 8

A.Carbon-14 and hydrogen-3 would be more likely to decay, because their neutrons and protons are not equal.
B. Oxygen-16 would be more likely to decay, because it has the largest atomic mass.
C. Oxygen-16 would be more likely to decay, because its neutrons and protons are equal.
D.Carbon-14 and oxygen-16 would be more likely to decay, because their atomic numbers are higher.

Answers

Answered by danidavis21
0

Answer:

Explanation:

not rght answer took test and got it wrong

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