Math, asked by arnabdgp14, 1 year ago

examine weather  15^{n} n can end witha digit 0 for any n belongs to a natural number

Answers

Answered by VISA006
3
No,  15^{n} cannot  end with digit 0 for any n belongs to a natural number

arnabdgp14: why .....?????????????
arnabdgp14: plz....show me the solution........
VISA006: to end in 0, the prime factorisation of 15 should contain 2 and 5. but it does not. so it cannot end in 0
Anonymous: yeah,right
Answered by Anonymous
2
we know that 15^n = 3^n*5^n
but,none of the multiples of 3 and 5 give a no.which is divisible by 2 and 5,thus,it's not possible

arnabdgp14: are u in 10 th ????????????
Anonymous: i was in till last year,but changed into stateboard this year
Anonymous: yes,i am in
arnabdgp14: whjich state are u from ????????????
Anonymous: kerala
arnabdgp14: ooooooooooooo
Anonymous: y r u repeating ?
arnabdgp14: jst like that
arnabdgp14: gd bye and thnx 4 the answer..............
Anonymous: bye
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