Question

examine wether (x - 2) is a factor of x² + 2x - 8​

Answer 1

Answer:

Yes.

Step-by-step explanation:

According to factor theorem (x-a) is a factor of f(x) if f(a) =0

f(x) =

${x}^{2} + 2x - 8$

f(2) =

${2}^{2} + 2 \times 2 - 8 \\ = 4 + 4 - 8 \\ = 8 - 8 \\ = 0$

Therefore (x-2) is a factor of x^2+2x-8.