Question

examine wheater x+2 us a factore of x³+3x²+5x+6​

Answer 1

Step-by-step explanation:

Let, f(x) = x³+3x²+5x+6

x+2 = 0

x = -2

Now,

f(-2) = (-2)³+3(-2)²+5(-2)+6

= -8+12-10+6

=0

So, x+2 is zero of polynomial f(x).

Answer 2

Answer:

x³+3x²+5x+6=0.

x+2=0.

x=-2.

substituting x=-2.

(-2)³+3(-2)²+5(-2)+6=0.

(-8)+3(4)-10+6=0.

-8+12-10+6=0.

-18+18=0.

0=0.

I think this is your answer.