Question

examine wheather the root 7.are rational or irrational​

Answer 1

$\sqrt{7}$ is irrational

as it does not have a terminating or repeating decimal expansion

PLEASE MARK AS BRAINLIEST!!!

Answer 2

Answer:

√7 is obviously irrational

Step-by-step explanation:

Let us assume that 7 is rational. Then, there exist co-prime positive integers a and b such that 7

=

b

a

⟹a=b

7

Squaring on both sides, we get

a

2

=7b

2

Therefore, a

2

is divisible by 7 and hence, a is also divisible by7

so, we can write a=7p, for some integer p.

Substituting for a, we get 49p

2

=7b

2

⟹b

2

=7p

2

.

This means, b

2

is also divisible by 7 and so, b is also divisible by 7.

Therefore, a and b have at least one common factor, i.e., 7.

But, this contradicts the fact that a and b are co-prime.

Thus, our supposition is wrong.

Hence,

7

is irrational.