Math, asked by haree71, 11 months ago

examine whether(2-root2) (2+root2) are rational or irrational​

Answers

Answered by pariharbalwanooo
12

Answer:

Step-by-step explanation:

(2-root2) (2+root2)

(a+b) (a-b) =a²-b²

2²-(root2)²

4-2=2

That is rational number.

Answered by ushmagaur
1

Question: Examine whether (2-\sqrt{2} )(2+\sqrt{2} ) is rational or irrational.

Answer:

The expression (2-\sqrt{2} )(2+\sqrt{2} ) is rational.

Step-by-step explanation:

Irrational number: The number which cannot be written in the p/q form, q≠0, where p and q are integers.

Rational number: The number which can be written in the p/q form, q≠0, where p and q are integers.

Recall the identity,

(a+b)(a-b)=a^2-b^2

Step 1 of 1

As we know that,

The number 2 is a rational number and the number \sqrt{2} is an irrational number.

To check: (2-\sqrt{2} )(2+\sqrt{2} ) is rational or irrational.

Consider the expression as follows:

(2-\sqrt{2} )(2+\sqrt{2} )

Here, a=2 and b=\sqrt{2}

Simplify the expression using the identity as follows:

2^2-(\sqrt{2} )^2

4-2

2

(2-\sqrt{2} )(2+\sqrt{2} )=2

Notice that the number 2 is a rational number.

Therefore, the expression (2-\sqrt{2} )(2+\sqrt{2} ) is rational.

#SPJ2

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