Question

Examine whether t-2 is a factor of palynomial 2t^3-t^2-16^t+20

Answer 1

Answer:

put the value of 2 in the equation

so I will get

16-4-32+20=0

hence it is a factor of the polynomial

I can use this trick in all polynomial

Hope it will help you

Answer 2

Answer:

$\boxed{yes}$

Step-by-step explanation:

$\green{Verification}$

To check that t-2 is a factor of

$\underline{2t^3-t^2-16t+20}$

we need to put the value

x=2 in the given polynomial

if the value becomes 0 the it is a factor

$=2(2) {}^{3} - (2) {}^{2} - 16(2) + 20$

$= 16 - 4 - 32 + 20$

$= 12 - 32 + 20$

$= - 32 + 32$

$= 0$

now the value becomes 0

then it is a factor of the given polynomial

hence

$\boxed{verified}$