Question

Examine whether
${x}^{2} - 2x + 1 = 0$
has real roots. If so find the roots. ​

Answer 1

Answer:

Step-by-step explanation:

$\sf{\green{Given,\,\,expression\,\,is\,\, x^{2}-2x+1=0}}$

Now,

let, its discriminant be denoted by 'D', so,

$\rm{\purple{D=(-2)^{2}-4\cdot1\cdot1}}$

$\rm{\purple{\implies\,D=4-4}$

$\rm{\purple{\implies\,D=0}$

So, the given equation has real roots.

$\large{\bullet\,\pink{\tt{Finding\,\,roots\,\,:}}}$

$\sf{x^{2}-2x+1=0}$

$\sf{\implies\,(x-1)^{2}=0}$

$\sf{\implies\,(x-1)(x-1)=0}$

So, its roots are 1 and 1