Question

examine whether the following numbers are rational or irrational(3+root2) (2-root3) (3-root2) ​

Answer 1

Explanation:

For (3+√2)

=let (3+√2) be x

=> x^2= (3+√2)^2

=> x^2= 3^2 +(√2)^2+ 2×3×√2

=> x^2= 9+2+6√2

=> x^2= 11+6√2

=>x^2-11=6√2

here we can see that x= rational

but 6√2= irrational

therefore (3+√2) is irrational number!

I hope it helps you

Answer 2

Answer:

because in all statements there was root

so this is

irrational number