Examine whether the following numbers are rational or irrational with justification
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Step-by-step explanation:
Given :-
(3+√5)^2 and (2+√2)(2-√2)
To find:-
Examine whether the following numbers are rational or irrational with justification.
Solution:-
1)Given number = (3+√5)^2
It is in the form of (a+b)^2
Where a = 3 and b=√5
(a+b)^2 = a^2+2ab+b^2
(3+√5)^2
=> 3^2+2(3)(√5)+(√5)^2
=>9+6√5+5
=> 14+6√5
(3+√5)^2 = 14+6√5
(3+√5)^2 is an irrational number.
2) Given number = (2+√2)(2-√2)
It is in the form of (a+b)(a-b)
Where a = 2 and b=√2
We know that
(a+b)(a-b)=a^2-b^2
(2+√2)(2-√2) = 2^2 - (√2)^2
=> 4-2
=> 2
(2+√2)(2-√2) = 2
(2+√2)(2-√2) is a rational number.
Answer:-
1)(3+√2)^2 is an irrational number
2)(2+√2)(2-√2) is a rational number.
Used formula:-
- (a+b)^2 = a^2+2ab+b^2
- (a+b)(a-b)=a^2-b^2
- q is a rational number and s is an irrational number then q+s , q-s,qs and q/s are also irrational numbers.
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