Examine whether the following quadratic equations have real roots or not:
x2 — 10x + 2 = 0
Answers
Answered by
3
Step-by-step explanation:
compare with ax2+bx+c
a=1 ; b= -10; c = 2
b2-4ac
100-8 = 92..... value is positive and more than 0
then root are real
Answered by
2
Answer:
the roots are not real because,,,,,
Step-by-step explanation:
Given quadratic equation is x²-10x+2
comparing the above equation with ax²+bx+c ,
therefore, a=1, b=-10 and c=2
b²-4ac=(-10) ²-4×1×2
=100-8
=92
x=-b±√b²-4ac/2a=0
=10±√92/2=0
=10±2√23/2=0
=10+2√23/2=0 or
10-2√23/2=0
= 14.79858 or 5 .20
both the roots are greater than zero
therefore roots are not real of the given quadratic equation....
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