Examine whether x – 1 is a factor of following
i) 8x4 – 12x3 + 18x + 14
iii) x3 + 8x2 – 7x – 2
Answers
Answered by
2
Step-by-step explanation:
X-1=0
X=1
i) p(x) =0
8x4 - 12x3 + 18 x1 +14
=32 - 36 +18 +14
=30
ii) 1x3+ 8x2-7x1-2
=3+16-7-2
=10
Therefore it is not a factor
Answered by
6
x - 1 = 0
x = 1
putting values of x in the equations
8 x ^4 - 12 x ^3 + 18 x + 14 = 0
8 (1)^4 - 12 (1)^3 + 18 (1) + 14 = 0
8 - 12 + 18 + 14 = 0
- 4 + 32 = 0
28 is not equal to 0
so 8 x ^4 - 12 x ^3 + 18 x + 14 is not a factor of x - 1.
2 . x ^3 + 8x^2 - 7 x - 2
putiing value of x
(1)^3 + 8(1)^2 - 7(1) - 2 = 0
1 + 8 - 7 -2 = 0
9 - 9 = 0
0=0
so x ^3 + 8x^2 - 7 x - 2 is a factor of x-1
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