Question

.Examine Whether (x-3) is a factor of x^3-4x^2+x+6.

Answer 1

$\huge\bf\purple{Polynomials}$

First we will find the the zero of x-3 that will be-

$x - 3 = 0$

$x = 0 + 3$

$x = 3$

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Now,

$p(x) = x {}^{3} - 4x {}^{2} + x + 6$

$p(3) =(3)^{3} - 4(3) {}^{2} + (3) + 6$

$=>27 - 36 + 3 + 6$

$= > 0 \: ans$

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$\therefore$ x-3 is the factor.

Answer 2

Step-by-step explanation:

x-3=0

x=3

On putting 3 in place of x,

=3^3-(4*3^2)+3+6

=27-144+9

=27-135

=(-108) Ans.