Question

Examine (x+2) is a factor of x3+2x2+3x+6

Answer 1

this is the answer in a short method I hope you will get it

Answer 2

Answer:

Hope it helps

plz mark it as brainliest

Step-by-step explanation:

=  put divisor as 0

x+2=0

x=-2

Let p(x) =x3+2x2+3x+6

since x=-2

p(-2)=(-2)3+2(-2)2+3(-2)+6

p(-2)= -8 +8 -6 +6

p(-2)= 0

therefore, remainder is 0

x+2 i a factor of p(x)