Question

examini whether(x-1) is a




factor of 4x'3+5x'2_3x+6

Answer 1

Answer:

Step-by-step explanation:

Answer 2

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putting
x-1=0
x=1

now putting:-
p(x)=4x³+5x²-3x+6

p(1)=4(1)³+5(1)²-3(1)+6
=4+5-3+6
=9-3+6
=6+6
=12
12 not equal to zero

that is why x-1 is not a factor of the given polynomial...


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