Example 1.1 A copper wire, 2 m long and 6.25 x 10 m² in cross-section, is
found to stretch 3 x 10-3 m under a tension of 1 x 103 N. What is the Young's
modulus of the material of the wire?
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ANSWER
Given that,
Young modulus Y=1.26×10
12
dyne/cm
Area A=1cm
2
As the length of the wire is doubled, the change in length is equal to its
original length.
If L is the original length
Then, Δl=l
We know that,
Y=
A×ΔL
F×L
F=Y×A
F=0.126×10
12
×1×10
−4
F=1.2×10
7
N
Hence, the force is 1.2×10
7
N
Answered By
toppr
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