Question

Example 1.1 A copper wire, 2 m long and 6.25 x 10 m² in cross-section, is
found to stretch 3 x 10-3 m under a tension of 1 x 103 N. What is the Young's
modulus of the material of the wire?​

Answer 1

Answer:

ANSWER

Given that,

Young modulus Y=1.26×10

12

dyne/cm

Area A=1cm

2

As the length of the wire is doubled, the change in length is equal to its

original length.

If L is the original length

Then, Δl=l

We know that,

Y=

A×ΔL

F×L

F=Y×A

F=0.126×10

12

×1×10

−4

F=1.2×10

7

N

Hence, the force is 1.2×10

7

N

Answered By

toppr

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