Question

Example 1.15. At S.T.P. calculate the number
of molecules in 11.2 litre Nitrogen.​

Answer 1

Explanation:

Moles of NO

Moles of NO 2

Moles of NO 2

Moles of NO 2 =

Moles of NO 2 = 22400

Moles of NO 2 = 22400112

Moles of NO 2 = 22400112

Moles of NO 2 = 22400112 =5×10

Moles of NO 2 = 22400112 =5×10 −3

Moles of NO 2 = 22400112 =5×10 −3 mol

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 g

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 =

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = Density

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass =

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.15

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mL

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3 ×6.023×10

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3 ×6.023×10 23

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3 ×6.023×10 23 =3.1×10

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3 ×6.023×10 23 =3.1×10 21

Moles of NO 2 = 22400112 =5×10 −3 molMass of NO 2 =5×10 −3 ×46 g=0.23 gVolume of NO 2 = DensityMass = 1.150.23 =0.2 mLNumber of molecule =5×10 −3 ×6.023×10 23 =3.1×10 21 .