Question

EXAMPLE 1.2
Metal M forms two oxides A and B in which the ratio of the number of oxygen atoms to the total
number of atoms present in the molecule is 3 : 5 and 1 : 2, respectively. Determine the formulae
of A and B.​

Answer 1

Answer:

In the first ratio 3 : 5 the total no of oxygen = 3y and total no of metals = 5y - 3y = 2y

Now the formula of A is M2O3

In the second ratio 1 :2 , the total no of oxygen = 1z and total no of metals = 2z - 1z = 1z

Now the formula of B is MO

Explanation:

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