Example 1.6: In an experiment to determine the volume of an object, mass and density are recorded as m= (5 + 0.15) kg and p = (5 +0.2) kg m respectively. Calculate percentage error in the measurement of volume.
Answers
Explanation:
need not be a square number.
example – 30, 11, 24, 65, 99For loss of 10%, Rs.99=90%×CP
1
⟹CP
1
=Rs.110
For profit of 10%, Rs.99=110%×CP
2
⟹CP
2
=Rs.90
Total CP=Rs.(110+90)=200
TotalSP=99+99=198
Gain%=
100
200−198
×100=1%
Answer:
The percentage error in the measurement of volume is 7%.
Explanation:
Given that,
Mass = (5+0.15) kg
Density = (5+0.2) kg/m^3
We need to calculate the percentage error in the measurement of volume.
Using formula of volume
\dfrac{\Delta V}{V}\times100=\dfrac{\Delta M}{M}\times100}+\dfrac{\Delta \rho}{\rho}\times100
Put the value into the formula
\dfrac{\Delta V}{V}\times100=\dfrac{0.15}{5}\times100+\dfrac{0.2}{5}\times100
V
ΔV
×100=
5
0.15
×100+
5
0.2
×100
\dfrac{\Delta V}{V}\times100=7\%
V
ΔV
×100=7%
Hence, The percentage error in the measurement of volume is 7%