Question

Example 1.7 : In a reaction, 0.5 mol of aluminium is required. Calcula
amount of aluminium required in grams? (atomic mass of Al = 27 amu)​

Answer 1

Given

• In a reaction we need 0.5 mol of aluminium
• Atomic Mass of Aluminium = 27 amu

To Find

• Amount of aluminium required in grams

Solution

☯ Grams = Moles × Atomic Mass

So here we have that,

• For a reaction to take place 0.5 moles of aluminium is required and we ought to convert Moles to grams

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✭ According to the Question :

→ Grams = Moles × Atomic Mass

• Moles = 0.5 amu
• Atomic Mass = 27 amu

→ Grams = 0.5 × 27

→ Grams = 13.5 g

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Know More

• Formula to find number of Moles = Grams of Compound/Molar Mass
• Formula to find Molecular Mass = Atomic Number × Atomic Weight

Answer 2

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☛To find

✒Amount of aluminium required in grams

✇Solution

✧Grams=Moles×Atomic Mass

Answer

✒Grams=Moles×Atomic Mass

☛ Moles=0.5amu

☛Atomic Mass=27amu

☛Grams=0.5×27

Grams=13.5g

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