Math, asked by sonusharma4201434, 9 months ago


Example 1: A boat goes 30 km
upstream and 44 km downstream in
10 hours. In 13 hours, it can go
40 km upstream and 55 km
down-stream. Determine the speed
of the stream and that of the boat in
still water​

Answers

Answered by anushree9192
0

Step-by-step explanation:

Let the speed of the stream =x=x km/hr

Let the speed of the boat in still water =y=y km/hr

Upstream speed =y-x=y−x km/hr

Downstream speed =y+x=y+x km/hr

time=\dfrac{distance}{speed}time=

speed

distance

The boat goes 3030 km upstream and 4444 km downstream in 1010 hours.

Time taken =\dfrac{30}{y-x}+\dfrac{44}{y+x}=

y−x

30

+

y+x

44

10=\dfrac{30}{y-x}+\dfrac{44}{y+x}10=

y−x

30

+

y+x

44

................. (1)

The boat goes 4040 km upstream and 5555 km downstream in 1313 hours.

Time taken =\dfrac{40}{y-x}+\dfrac{55}{y+x}=

y−x

40

+

y+x

55

13=\dfrac{40}{y-x}+\dfrac{55}{y+x}13=

y−x

40

+

y+x

55

.................. (2)

Let \dfrac{1}{y-x}=u

y−x

1

=u

and \dfrac{1}{y+x}=v

y+x

1

=v

From (1) and (2),

30u+44v=1030u+44v=10 ...................(3)

40u+55v=1340u+55v=13 ...................(4)

Multiply equation (3) with 4 and equation (4) with 3,

120u+176v=40120u+176v=40 ........... (5)

120u+165v=39120u+165v=39 ........... (6)

subtract equation (6) from (5),

176v-165v=40-39176v−165v=40−39

11v=111v=1

v=\dfrac{1}{11}v=

11

1

\Rightarrow \dfrac{1}{y+x}=\dfrac{1}{11}⇒

y+x

1

=

11

1

y+x=11y+x=11 .......................... (7)

From equation (3),

30u=10-44v30u=10−44v

30u=10-44\times \dfrac{1}{11}30u=10−44×

11

1

30u=10-4=630u=10−4=6

u=\dfrac{1}{5}u=

5

1

\dfrac{1}{y-x}=\dfrac{1}{5}

y−x

1

=

5

1

\Rightarrow y-x=5⇒y−x=5 .................. (8)

Adding (7) and (8), we get,

2y=162y=16

y=8y=8

From equation (7),

x=11-yx=11−y

x=11-8=3x=11−8=3

Answered by BendingReality
2

Answer:

Speed of stream = 3 km / hr.

Speed of boat in still water = 8 km / hr.

Step-by-step explanation:

Let the speed of the boat in still water be a km / hr and stream be b km / hr

For upstream = a - b

For downstream = a + b

We know :

Speed = Distance / Time

Case 1 .

10 = 30 / a - b + 44 / a + b

Let 1 / a - b = x and 1 / a + b = y

30 x + 44 y = 10 ... ( i )

Case 2 .

13 = 40 / a - b + 55 / a + b

40 x + 55 y = 13 ... ( i )

Multiply by 4 in ( i ) and by 3 in ( ii )

120 x + 176 y = 40

120 x = 40 - 176 y ... ( iii )

120 x + 165 y = 39

120 = 39 - 165 y ... ( iv )

From ( iii )  and  ( iv )

40 - 176 y = 39 - 165 y

11 y = 1

y = 1 / 11

120 x = 40 - 176 y

120 x = 40 - 176 / 11

x = 1 / 5

Now :

1 / a - b = 1 / 5

a - b = 5

a = 5 + b ... ( v )

1 / a + b = 1 / 11

a + b = 11

a = 11 - b ... ( vi )  

From ( v  ) and ( vi )

11 - b = 5  + b

2 b = 6

b = 3

a = 5 + b

a = 5 + 3

a = 8

Hence we get answer.

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