Question

Example 1. An iron ball of mass 3 kg is
released from a height of 125 m and falls
freely to the ground. Assuming that the
value of g is 10 m/s, calculate
(i) time taken by the ball to reach the
ground
(ii) velocity of the ball on reaching the
ground
(iii) the height of the ball at half the time it
takes to reach the ground.
Given: m = 3 ka distance​

Answer 1

Answer:

HI MATE IT'S A VERY GOOD QUESTION. SO SEE THE SOLUTION HERE

Explanation:

GIVEN THE MASS OF THE BALL IS 3 Kg AND THE HEIGHT IS 125m

(i)SO THE TIME TAKEN TO REACH THE GROUND

WILL BE

= u/g

=√2gh/g

=5 s

(ii)VELOCITY OF THE BALL ON REACHING THE GROUND WILL BE = 50 m/s

(iii) HEIGHT OF THE BALL WILL BE AT HALF A TIME WILL BE

= 125 - 1/2×10×(2.5)^2 m

= 125 - 31.25 m

=93.75 m

PLEASE MARK ME AS THE BRAINLIEST. ::))