Example 1. Find the gravitational force between
earth and an object of 2 kg mass placed on its
surface. (Given, mass of the earth = 6 x 1024 kg and
radius of the earth = 6.4 x 106 m)
Answers
Answered by
2
Explanation:
g=m1*m2/r^2
g= 2*6*10^24/6.4*10^6
g= 12*10^24-6/6.4
g= 12*10^18/6.4
g=1.875*10^18
g= 1875 *10^15
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Answered by
3
Answer:
Mass of Earth, M = 6 × 10^24 kg
Mass of object, m = 1 kg
Universal gravitational constant,
G = 6.7 × 10^−11 Nm^2 kg^−2
r = radius of the Earth (R) ( ob. is on the surface of earth)
r = R = 6.4 × 10^6 m
Therefore, the gravitational force
F = GMm / r^2
= (6.7 × 10^-7 × 6 × 10^24 × 1)/ (6.4 ×10^4)^2
= 9.8 N
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