Question

Example 1: Mahendra and Virat are sitting
at a distance of 1 metre from each other. Their
Solsed ex
masses are 75 kg and 80 kg respectively.
What is the gravitational force between them?
​

Answer 1

Answer:

question⬇

➡ Mahendra and Virat are sitting at a distance of 1 metre from each other they solved at masses are 75 kg and 80 kg respectively what is the gravitational force between them?

Answer⬇

➡Given : r = 1 m, m1 = 75 kg, m2 = 80 kg and G = 6.67 x 10 -11 Nm2/kg2 According to Newton’s law, The gravitational force between Mahendra

Answer 2

Given:

Radius = 1m

Mass = m1 = 75

= m2 = 80

Formula Used:

F = GM1M2/r

Solution:

F = G×75×80÷1

= 6.67 × 10-11 ( 10 raise to power -11) ×75×80

= 4.002× 10-7 ( 10 raise to power -7)J

Answer:

4.002×10-7 J