Question

Example 1 : Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? Given : r=1 m,m 1 =75 kg,m 2 =80 kg and G = 6.67 * 10 ^ - 11 * N * m ^ 2 / k * a ^ 2​

Answer 1

Answer:

$4.002*10^-7 N$

Step-by-step explanation:

F=(G×m1×m2)/d^2  

F=(6.67×〖10〗^(-11)×75×80)/1^2  

F=4.002×〖10〗^(-7) N

Answer 2

Given:-

• r = 1 m
• $\sf{m_1}$ = 75 kg
• $\sf{m_2}$ = 80 kg
• G = 6.67 × $\sf{10^{-11}}$

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To find:-

• Gravitational force between them.

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Solution:-

${\dag}\:{\underline{\boxed{\sf{\purple{According\: to\: Newton's\: law}}}}}$

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$\tt\longmapsto{F = \dfrac{Gm_1 m_2}{r^2}}$

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$\tt\longmapsto{F = \dfrac{6.67 \times 10^{-11} \times 75 \times 80}{1^2} n}$

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$\sf\longmapsto{\boxed{\pink{4.002 \times 10^{-7} N}}}$

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Hence,

• the gravitational force between Mahendra and Virat is $\sf{4.002 \times 10^{-7} N}$