Example 1 : Show that each angle of a rectangle is a right angle.
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et us recall what a rectangle is.
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Explanation:
Let, ABCD be a rectangle.
We have to prove that ∠A=∠B=∠C=∠D=90o
We know that a rectangle is parallelogram where its one angle is 90o.
Let us assume ∠A=90o
Now,
AD∥BC[oppositesidesofaparallelogramareparallel]
And AB is transversal.
So, ∠A+∠B=1800[interioranglesonthwsamwsideofatransversalaresupplementary]⇒90o+∠B=1800⇒∠B=90o
Again, we know that opposite angles of a parallelogram are equal.
∴∠C=∠A and ∠D=∠B
∴∠C=90o and ∠D=90o
∴∠A=∠B=∠C=∠D=90o
Hence, it is proved that ABCD is a rectangle.
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thanks for points......
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