Question

Example 1. Suppose the orbit of a satellite
is exactly 35780 km above the earth's
surface. Determine the tangential velocity
of the satellite​

Answer 1

Answer:

The tangential velocity of the satellite will be 3.07 km/s

Explanation:

The tangential velocity of a satellite is given by the relation;

v = √(GM/r)

G = gravitational cons * tan t = 6.67 * 10 ^ - 11 M = mass of earth = 5.972 x 1024 kg

r = radius of orbit = height + radius of earth

=> r = 35780 +6371 = 42151 km = 42151 x

10³ m

hence,

v = √(6.67 x 10-11 x 5.972 x 1024 /42151 x

10³)

= 3.07 x 10³ m/s

= 3.07 km/s

Hence the tangential velocity of the satellite will be 3.07 km/s