Question

Example 1:
The manager of ABC company is interested in estimating the total sale in thousands for all of
its 300 branches. From last year record, the total sale in thousands for all the 300 branches is
21300. A sample of size 15 branches is selected by SRSWOR and the observations are recorded as
follows. (tabulated sale values ate in thousands)
Branch No
15
Last Year sale(X) 25
30 15101235 5040 100 150 50 50 250 100
Current Year sale(Y) 30
11 26 18
22 48 5683 55 95 70 73
165
Obtain required estimate by (i) SRSWOR (ii) Ratio estimate calculate their variances and
compare them.
1
2
4
5
6
S
9
10
11
12
13​

Answer 1

Explanation:

\huge \fbox \red{\fbox{Answer}}

Answer

\large \bf{Given:}Given:

\sf \mapsto{Mass \: of \: baby(m)=500g= \frac{500}{1000} kg = 0.5kg}↦Massofbaby(m)=500g=

1000

500

kg=0.5kg

\sf \mapsto{Initial \: velocity(u)=54km/h=54 \times \frac{5}{18} m/s = 15m/s}↦Initialvelocity(u)=54km/h=54×

18

5

m/s=15m/s

\sf \mapsto{Time \: taken(t)=6sec}↦Timetaken(t)=6sec

\large \bf{To \: find:}Tofind:

\sf \leadsto{Force \: acting \: on \: baby. }⇝Forceactingonbaby.

\large \bf{Concept \: used:}Conceptused:

\sf \rightarrow{Final \: velocity(v) \: of \: baby \: is \: 0m/s.}→Finalvelocity(v)ofbabyis0m/s.

\large \bf{Formula \: used:}Formulaused:

\boxed {\bf{Acceleration \: of \: baby(a) = \frac{Final \: velocity - Initial \: velocity}{Time} = \frac{v - u}{t} }}

Accelerationofbaby(a)=

Time

Finalvelocity−Initialvelocity

=

t

v−u

\boxed {\bf{Force=Mass×Acceleration = ma}}

Force=Mass×Acceleration=ma

\large \bf{According \: to \: Question:}AccordingtoQuestion:

\sf \implies{Acceleration \: of \: baby(a) = \frac{Final \: velocity - Initial \: velocity}{Time} = \frac{v - u}{t} }⟹Accelerationofbaby(a)=

Time

Finalvelocity−Initialvelocity

=

t

v−u

\sf \implies{Acceleration \: of \: baby(a) = \frac{0- 15}{6} = \frac{- 15}{6} = - 2.5m/ {s}^{2} }⟹Accelerationofbaby(a)=

6

0−15

=

6

−15

=−2.5m/s

2

\bf{Then,}Then,

\sf \implies{Force=Mass×Acceleration}⟹Force=Mass×Acceleration

\sf \implies{Force=0.5×2.5=1.25N}⟹Force=0.5×2.5=1.25N

\bf{Hence, Force \: acting \: on \: baby \: is \: 1.25 \: newton.}Hence,Forceactingonbabyis1.25newton.

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