Example 10.1 The mass of the earth is
6 x 10²⁴ kg and that of the moon is
7.4 x 10²² kg. If the distance between the
earth and the moon is 3.84x105 km,
calculate the force exerted by the earth on
the moon. (Take G=6.7 ×10-¹¹N m2²kg-²)
Answers
Answer:
2.02 × 10^20
Explanation:
Here the explanation
the mass of the earth, M=6 × 10^24
the mass of the moon, m=7.4 × 10^22
the distance between the easy and the moon,
d = 3.84 × 10^5 km
= 3.84 × 10^5 × 1000
= 3.84 × 10^8 m
G = 6.7 × 10^-11 N m^2/kg^2
the force exerted by the earth on the moon,
F = G M × m
= 6.7 × 10^-11 N m^2/kg^2× 6 × 10^24 kg × 7.4 × 10^2 kg / (3.84 × 10^8 m)^2
= 2.02 × 10^20 N
Answer:
2.02 × 10¹⁹ N
Explanation:
Given :
Mass of earth = 6 × 10²⁴ kg
Mass of moon = 7.4 × 10²² kg
Distance between them = 3.84 × 10⁵ km = 3.84 × 10⁸ m
We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²
We have to find force :
We have :
F = G m₁ m₂ / r²
F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / ( 3.84 × 10⁸ )² N
F = 2.02 × 10¹⁹ N
Hence force exerted by the earth on the moon is 2.02 × 10¹⁹ N.