Physics, asked by kimtaeya, 9 months ago

Example 10.1 The mass of the earth is
6 x 10²⁴ kg and that of the moon is
7.4 x 10²² kg. If the distance between the
earth and the moon is 3.84x105 km,
calculate the force exerted by the earth on
the moon. (Take G=6.7 ×10-¹¹N m2²kg-²)​

Answers

Answered by hujare2000
7

Answer:

2.02 × 10^20

Explanation:

Here the explanation

the mass of the earth, M=6 × 10^24

the mass of the moon, m=7.4 × 10^22

the distance between the easy and the moon,

d = 3.84 × 10^5 km

= 3.84 × 10^5 × 1000

= 3.84 × 10^8 m

G = 6.7 × 10^-11 N m^2/kg^2

the force exerted by the earth on the moon,

F = G M × m

= 6.7 × 10^-11 N m^2/kg^2× 6 × 10^24 kg × 7.4 × 10^2 kg / (3.84 × 10^8 m)^2

= 2.02 × 10^20 N

Answered by BendingReality
3

Answer:

2.02 × 10¹⁹ N

Explanation:

Given :

Mass of earth = 6 × 10²⁴ kg

Mass of moon = 7.4 × 10²² kg

Distance between them = 3.84 × 10⁵ km = 3.84  × 10⁸ m

We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²

We have to find force :

We have :

F = G m₁ m₂ / r²

F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / (  3.84 × 10⁸ )² N

F = 2.02 × 10¹⁹ N

Hence force exerted by the earth on the moon is 2.02 × 10¹⁹ N.

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