Question

example 10 : If sin 3a = cos (a-26 degree ) , where 3a is an acute angle, find the value of a
I need proper step by step explanaition plzz

Answer 1

Answer:

A = 58

Step-by-step explanation:

Sin 3a = cos ( a - 26)

Sin 3a = sin [90 - ( a - 26)] (since, cos a = sin (90 - a)

3a = 90 - a +26

2a = 116

A = 58

please appreciate the efforts

mark as brainliest

Answer 2

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

$\sin(3a) = \cos(a - 26)$

We will use the formula :- Sin a = Cos (90 - a).

So,

$\leadsto \cos(90 - 3a) = \cos(a - 26)$

Therefore,

$\leadsto 90 - 3a = a - 26$

$\leadsto 116 = 4a$

$\leadsto a = 29$

______________

MORE SUCH FORMULAS :-

• Sin a = Cos (90 - a)
• Cos a = Sin (90 - a)
• Tan a = Cot (90 - a)
• Cot a = Tan (90 - a)
• Cosec a = Sec (90 - a)
• Sec a = Cosec (90 - a)

______________