Question

Example-10. Mary told her daughter, "Seven years ago, I was seven times as old as you were
then. Also, three years from now, I shall be three times as old as you will be." Find the present
age of Mary and her daughter.

linear equations in two variable​

Answer 1

Answer:

let us assume that Mary age is x years

and her daughter age is y years

7 years ago,

Mary age was x-7 years

her daughter age was y-7 years

according to question, x-7=7(y-7)

x-7=7y-49

x-7y=-42

3 years after,

Mary age will be x+3 years

her daughter age will be y+3 years

according to question,

x+3=3(y+3)

x+3=3y+9

x-3y=6

now solve both equation

subtract eq. x-7y=-42 from x-3y=6

we get,4y=48

y=12put it any equation, we get

x=42

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